30, డిసెంబర్ 2024, సోమవారం
26, డిసెంబర్ 2024, గురువారం
India mourns the loss of one of its most distinguished leaders
Former Indian prime minister Manmohan Singh has died at the age of 92.
Singh was one of India's longest-serving prime ministers and he was considered the architect of key liberalising economic reforms, as PM from 2004-2014 and before that as finance minister.
25, డిసెంబర్ 2024, బుధవారం
win10 performance settings, 40 best tools in Ai, 1. ChatGPT 2. DALL-E 3. Midjourney 4. Paradox 5. Textio 6. Tome 7. Slides AI 8. Lyric Studio 9. Sythesia 10. Fliki AI 11. Seo AI 12. Alli AI 13. Salesforce 14. Otter.ai 15. Github CoPilot
Regedit…2nd,
controlpanel,desktop press m , show menudisplay change 400 to 0
Run, msconfig,boot advsettings
processor count 1to max in the dropdown box
The Best AI Tools by Category
- Chatbots: ChatGPT, Claude
- Video Generation and Editing: Synthesia, Runway
- Writing: Rytr, Sudowrite
- Grammar and Writing Improvement: Grammarly, Wordtune
- Search Engines: Perplexity, ChatGPT search
- Social Media Management: Vista Social, FeedHive
- Image Generation: Midjourney, DALL·E 3
- Graphic Design: Canva Magic Studio, Looka
- App Builders: Bubble, Bolt
- Project Management: Asana, ClickUp
- Transcription and Meeting Assistants: tl;dv, Nyota
- Scheduling: Reclaim, Clockwise
- Customer Service: Tidio AI, Hiver
- Recruitment: Textio, CVViZ
- Knowledge Management: Notion AI Q&A, Guru
- Email: Hubspot Email Writer, SaneBox, Shortwave
- Presentations: Gamma, Presentations.ai
- Resume Builders: Teal, Kickresume
- Voice Generation: ElevenLabs, Murf
- Music Generation: Suno, Udio
23, డిసెంబర్ 2024, సోమవారం
22, డిసెంబర్ 2024, ఆదివారం
JEFF AGE IS 60 Yrs.......Adalf MARRIED JUST A HOUR BEFORE HIS DEPARTURE from this eternal world..........all are valid , .........................................
Sasanalu enka nirnaeanchabadaledu from the TRANSFORMERS movie.......
Optimus Prime: Any last words?
Demolishor: This is not your pla-anet to rule.
The Fallen shall rise again..
DESA BHASHALANDU TELUGU LESSA,.......... Telugu madhuryamu
on sunday my freetime
స్త్రీ జాతికీ ఏనాటికీ స్మరణీయ మహనీయ వీరాగ్రణికి.........
సౌందర్యమూ సౌశీల్యమూ నిలువెల్ల........
నెలకొన్న కలభాషిణికి
అభినందన మందారమాలదివి తానే భువిపైన దిగివచ్చెనా
అలలెక్కి ఆడింది అణువణువులో
20, డిసెంబర్ 2024, శుక్రవారం
19, డిసెంబర్ 2024, గురువారం
Feelings, nothing more than feelings Trying to forget my feelings of ...................
16, డిసెంబర్ 2024, సోమవారం
when you cross 45 years , expend ..... , save only 40%.................... , because u earned who will use......... by age 30
didn't get, Realistic support for my above statements, but the form is different
everybody will earn...............allocate some free time
15, డిసెంబర్ 2024, ఆదివారం
my free time , sunday
The voice of the lord Krishna to arjuna , the most powerful
You
can’t change what people feel about you so don’t try, just live your life be happy
next frame ……lust, anger, greed are the three
doors to hell
This is the only framers extension
Mr(mortal)…to lord……how these doors will get open, for whom
these doors will open, who will open
answer Mr don’t think …… they themselves know
better than us
ref:- lord is immortal ...........
Nobody kicks a dead dog.” Dale Carnegie: Time-Tested Methods for Conquering.
By ramu dayinaboyina
13, డిసెంబర్ 2024, శుక్రవారం
XML full length ,............i am going to implement soon ,Prerequisites html , css, java script these 3 concepts must thorough before going to xml
soon i will start 3 courses
Data structures using java or cpp or c any language
HCI human computer interaction
web programming up to xml.........
next jdbc servlets , jsp, java beans, ejbs, rmi, jndi, java mail.., JMS message system......complete server-side technologies.
4, డిసెంబర్ 2024, బుధవారం
DBMS........TRANSACTIONS, find the view Serializability ,conflict Serializability
Serializability is a type of property of DBMS in which each transaction is executed independently and automatically, even though these transactions are executed concurrently. In other words, we can say that if there are several transactions executed concurrently, then the main work of the serializability function is to arrange these several transactions in a sequential manner.
For better understanding, let's explain these with an example. Suppose there are two users ramu and ravi. Each executes two transactions. Let's transactions T1 and T2 are executed by ramu, and T3 and T4 are executed by ravi. Suppose transaction T1 reads and writes the data item A, transaction T2 reads the data item B, transaction T3 reads and writes the data item C and transaction T4 reads the data item D. Lets the schedule the above transaction as below.
- . T1: Read A → Write A→ Read B → Write B`
- • `T2: Read B → Write B`
- • `T3: Read C → Write C→ Read D → Write D`
- • ` T4: Read D → Write D
3, డిసెంబర్ 2024, మంగళవారం
Dekker’s Algorithm: Final and completed Solution – -Idea is to use favoured thread notion to determine entry to the critical section. Favoured thread alternates between the thread providing mutual exclusion and avoiding deadlock, indefinite postponement, or lockstep synchronization.
For this total 5 versions are there, the
final & perfect solution is the below one by ramu.
Main()
{
// to denote which thread will enter next
int favouredthread = 1;
// flags to indicate if each thread is in
// queue to enter its critical section
boolean thread1wantstoenter = false;
boolean thread2wantstoenter = false;
startThreads();
}
Thread1()
{
do {
thread1wantstoenter = true;
// entry section
// wait until thread2 wants to enter
// its critical section
while (thread2wantstoenter == true) {
// if 2nd thread is more favored
if (favaouredthread == 2) {
// gives access to other thread
thread1wantstoenter = false;
// wait until this thread is favored
while (favouredthread == 2)
;
thread1wantstoenter = true;
}
}
// critical section
// favor the 2nd thread
favouredthread = 2;
// exit section
// indicate thread1 has completed
// its critical section
thread1wantstoenter = false;
// remainder section
} while (completed == false)
}
Thread2()
{
do {
thread2wantstoenter = true;
// entry section
// wait until thread1 wants to enter
// its critical section
while (thread1wantstoenter == true) {
// if 1st thread is more favored
if (favaouredthread == 1) {
// gives access to other thread
thread2wantstoenter = false;
// wait until this thread is favored
while (favouredthread == 1)
;
thread2wantstoenter = true;
}
}
// critical section
// favour the 1st thread
favouredthread = 1;
// exit section
// indicate thread2 has completed
// its critical section
thread2wantstoenter = false;
// remainder section
} while (completed == false)
}
This version guarantees a complete solution to the critical solution problem.