rows = int(input("Enter number of rows: "))
for i in range(rows):
for j in range(i+1):
print(j+1, end=" ")
print()
// C++ implementation of the above approach
#include "bits/stdc++.h"
using namespace std;
// Function to return the word
// of the corresponding digit
void printValue(char digit)
{
// Switch block to check for each digit c
switch (digit) {
// For digit 0
case '0':
cout << "Zero ";
break;
// For digit 1
case '1':
cout << "One ";
break;
// For digit 2
case '2':
cout << "Two ";
break;
// For digit 3
case '3':
cout << "Three ";
break;
// For digit 4
case '4':
cout << "Four ";
break;
// For digit 5
case '5':
cout << "Five ";
break;
// For digit 6
case '6':
cout << "Six ";
break;
// For digit 7
case '7':
cout << "Seven ";
break;
// For digit 8
case '8':
cout << "Eight ";
break;
// For digit 9
case '9':
cout << "Nine ";
break;
}
}
// Function to iterate through every
// digit in the given number
void printWord(string N)
{
int i, length = N.length();
// Finding each digit of the number
for (i = 0; i < length; i++) {
// Print the digit in words
printValue(N[i]);
}
}
// Driver code
int main()
{
string N = "123";
printWord(N);
return 0;
}
Input: N = 1234
Output: One Two Three Four
Explanation:
Every digit of the given number has been converted into its corresponding word.
#
Python program to determine whether # the number is Armstrong number or not #
Function to calculate x raised to # the power y def power(x, y): if y == 0:
return 1 if y % 2 == 0: return power(x, y // 2) * power(x, y // 2) return x *
power(x, y // 2) * power(x, y // 2) # Function to calculate order of the number
def order(x): # Variable to store of the number n = 0 while (x != 0): n = n + 1
x = x // 10 return n # Function to check whether the given # number is
Armstrong number or not def isArmstrong(x): n = order(x) temp = x sum1 = 0
while (temp != 0): r = temp % 10 sum1 = sum1 + power(r, n) temp = temp // 10 #
If condition satisfies return (sum1 == x) # Driver code x = 153
print(isArmstrong(x)) x = 1253 print(isArmstrong(x))
# Multiplication
table (from 1 to 10) in Python
num = 12
# To take input
from the user
# num =
int(input("Display multiplication table of? "))
# Iterate 10
times from i = 1 to 10
for i in range(1,
11):
print(num, 'x', i, '=', num*i)
Input: N = 567
Output: Five Six Seven
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