8, ఆగస్టు 2025, శుక్రవారం

cyber security.............

 Volume-based attacks, also known as volumetric attacks, are a type of DDoS attack that flood a target with massive amounts of network traffic, overwhelming its resources and causing service disruptionsThese attacks are typically measured in bits per second (bps), packets per second (pps), or connections per second (cps). The goal is to saturate the target's bandwidth and processing power, making it unable to handle legitimate traffic


Application-based attacks exploit vulnerabilities in software applications to gain unauthorized access, disrupt functionality, or steal dataThese attacks can target various layers of an application, including the web, API, and mobile application layers. Common types include injection attacks, cross-site scripting (XSS), cross-site request forgery (CSRF), and denial-of-service (DoS/DDoS) attacks. 

A URL interpretation attack, also known as a semantic URL attack, occurs when an attacker manipulates the parameters of a URL to exploit vulnerabilities in how a web application interprets the URL's syntax and semantics. This can lead to unauthorized access to resources, modification of data, or other unexpected behavior


A dictionary attack is a type of cyberattack where hackers try to guess passwords by systematically trying words from a pre-defined list (a "dictionary") of common passwordsThis method exploits the fact that many people use predictable or easily guessed passwords. Attackers use automated tools to rapidly input these potential passwords until they find a match, gaining unauthorized access to systems or data


Protocol-based attacks are a type of DDoS (Distributed Denial of Service) attack that exploits weaknesses in network protocols, particularly at Layers 3 and 4 of the OSI modelThese attacks aim to disrupt a service by overwhelming a target's resources with malicious connection requests or by exploiting protocol vulnerabilities to exhaust server capacity. 

lab-4 python ..................

rows = int(input("Enter number of rows: "))


for i in range(rows):

    for j in range(i+1):

        print(j+1, end=" ")

    print()




 // C++ implementation of the above approach


#include "bits/stdc++.h"

using namespace std;


// Function to return the word

// of the corresponding digit

void printValue(char digit)

{


    // Switch block to check for each digit c

    switch (digit) {


    // For digit 0

    case '0':

        cout << "Zero ";

        break;


    // For digit 1

    case '1':

        cout << "One ";

        break;


    // For digit 2

    case '2':

        cout << "Two ";

        break;


    // For digit 3

    case '3':

        cout << "Three ";

        break;


    // For digit 4

    case '4':

        cout << "Four ";

        break;


    // For digit 5

    case '5':

        cout << "Five ";

        break;


    // For digit 6

    case '6':

        cout << "Six ";

        break;


    // For digit 7

    case '7':

        cout << "Seven ";

        break;


    // For digit 8

    case '8':

        cout << "Eight ";

        break;


    // For digit 9

    case '9':

        cout << "Nine ";

        break;

    }

}


// Function to iterate through every

// digit in the given number

void printWord(string N)

{

    int i, length = N.length();


    // Finding each digit of the number

    for (i = 0; i < length; i++) {


        // Print the digit in words

        printValue(N[i]);

    }

}


// Driver code

int main()

{

    string N = "123";

    printWord(N);

    return 0;

}


Input: N = 1234 
Output: One Two Three Four 
Explanation: 
Every digit of the given number has been converted into its corresponding word.

# Python program to determine whether # the number is Armstrong number or not # Function to calculate x raised to # the power y def power(x, y): if y == 0: return 1 if y % 2 == 0: return power(x, y // 2) * power(x, y // 2) return x * power(x, y // 2) * power(x, y // 2) # Function to calculate order of the number def order(x): # Variable to store of the number n = 0 while (x != 0): n = n + 1 x = x // 10 return n # Function to check whether the given # number is Armstrong number or not def isArmstrong(x): n = order(x) temp = x sum1 = 0 while (temp != 0): r = temp % 10 sum1 = sum1 + power(r, n) temp = temp // 10 # If condition satisfies return (sum1 == x) # Driver code x = 153 print(isArmstrong(x)) x = 1253 print(isArmstrong(x))

 

 

 

 

 

 

# Multiplication table (from 1 to 10) in Python

 

num = 12

 

# To take input from the user

# num = int(input("Display multiplication table of? "))

 

# Iterate 10 times from i = 1 to 10

for i in range(1, 11):

   print(num, 'x', i, '=', num*i)

 

Input: N = 567 
Output: Five Six Seven 

 

6, ఆగస్టు 2025, బుధవారం

ONE DOCTORATE SAID TO RAMU HE USES CHATGPT FOR EVERY TOPIC ...............RAMU ASKED HIM HOW MUCH U PAID TO BUY YOUR DOCTORATE .......my brother with degree is getting 24 lakhs salary per Anam In my department my colleague doctorate is getting 8 lakhs only Anam Big laugh by ramu………….. musth joke ah ah creaming............................................................

 

One doctorate said to ramu "he uses ChatGPT for every topic"

Ramu asked him how much u paid to buy your  doctorate

What a wonderful innocent doctorate I meat I laughed loudly  

The remain discussion read between the line



E=mc2 only for student, Scientist or phd.......... ramu quoted this stmt

and for u any change in the above eq.........................




my brother with degree is getting 24 lakhs salary per Anam


In my department my colleague doctorate is getting 8 lakhs only

Big laugh by ramu…………..

musth joke ah ah Screaming.......................